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You could be one of our future talents MAERSK INTERNATIONAL TECHNOLOGY & SCIENCE PROGRAMME Are you about to graduate as an engineer or geoscientist? Or have you already graduated? P. Moller - Maersk. com 60 Calculus 2c-10 Vector potentials and the tangential line integral is reduced to K U · dx π 2 = 3·3 π 2 = 9 0 = 9 0 = 9 π 2 π 2 0 = 9 0 (− cos t sin3 t, 0, cos4 t) · (− cos2 t sin t, − sin t, sin2 t cos t) dt cos3 t sin4 t + cos5 t sin2 t dt 3 2 2 cos t sin {sin t + cos t} dt = 9 (1 − sin2 t) sin2 t · cos t dt = 9 1 1 − 3 5 =9· π 2 2 1 0 cos3 t sin2 t dt 0 (u2 − u4 ) du 6 2 = .
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Com 59 Calculus 2c-10 Vector potentials I 1) It follows immediately that U is divergence free. Then rot U = ex ey ez ∂ ∂x ∂ ∂y ∂ ∂z −yz 0 xy = (x, −y − y, z) = (x, −2y, z). It follows from rot U(x) = 0 for x = 0, that U is not a gradient field. 2) We get from r(t) = cos3 t, 3 cos t, sin3 t that r (t) = −3 cos2 t sin t, −3 sin t, 3 sin2 t cos t , Please click the advert what‘s missing in this equation? You could be one of our future talents MAERSK INTERNATIONAL TECHNOLOGY & SCIENCE PROGRAMME Are you about to graduate as an engineer or geoscientist?